X^2+204x-4800=0

Solution for X^2+204x-4800=0 equation:

X^2+204X-4800=0

a = 1; b = 204; c = -4800;
Δ = b2-4ac
Δ = 2042-4·1·(-4800)
Δ = 60816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60816}=\sqrt{16*3801}=\sqrt{16}*\sqrt{3801}=4\sqrt{3801}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(204)-4\sqrt{3801}}{2*1}=\frac{-204-4\sqrt{3801}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(204)+4\sqrt{3801}}{2*1}=\frac{-204+4\sqrt{3801}}{2}
$